Optimal. Leaf size=115 \[ \frac{(B (n+1)+i A (1-n)) (c-i c \tan (e+f x))^n \text{Hypergeometric2F1}\left (1,n,n+1,\frac{1}{2} (1-i \tan (e+f x))\right )}{4 a f n}+\frac{(-B+i A) (c-i c \tan (e+f x))^n}{2 a f (1+i \tan (e+f x))} \]
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Rubi [A] time = 0.17909, antiderivative size = 115, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 41, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.073, Rules used = {3588, 78, 68} \[ \frac{(B (n+1)+i A (1-n)) (c-i c \tan (e+f x))^n \, _2F_1\left (1,n;n+1;\frac{1}{2} (1-i \tan (e+f x))\right )}{4 a f n}+\frac{(-B+i A) (c-i c \tan (e+f x))^n}{2 a f (1+i \tan (e+f x))} \]
Antiderivative was successfully verified.
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Rule 3588
Rule 78
Rule 68
Rubi steps
\begin{align*} \int \frac{(A+B \tan (e+f x)) (c-i c \tan (e+f x))^n}{a+i a \tan (e+f x)} \, dx &=\frac{(a c) \operatorname{Subst}\left (\int \frac{(A+B x) (c-i c x)^{-1+n}}{(a+i a x)^2} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{(i A-B) (c-i c \tan (e+f x))^n}{2 a f (1+i \tan (e+f x))}+\frac{(c (A (1-n)-i B (1+n))) \operatorname{Subst}\left (\int \frac{(c-i c x)^{-1+n}}{a+i a x} \, dx,x,\tan (e+f x)\right )}{2 f}\\ &=\frac{(i A (1-n)+B (1+n)) \, _2F_1\left (1,n;1+n;\frac{1}{2} (1-i \tan (e+f x))\right ) (c-i c \tan (e+f x))^n}{4 a f n}+\frac{(i A-B) (c-i c \tan (e+f x))^n}{2 a f (1+i \tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 63.2637, size = 111, normalized size = 0.97 \[ \frac{2^{n-1} \left (\frac{c}{1+e^{2 i (e+f x)}}\right )^n \left ((A (n-1)+i B (n+1)) e^{2 i (e+f x)} \text{Hypergeometric2F1}\left (1,1-n,2-n,1+e^{2 i (e+f x)}\right )+(n-1) (A+i B)\right )}{a f (n-1) (\tan (e+f x)-i)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.823, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( A+B\tan \left ( fx+e \right ) \right ) \left ( c-ic\tan \left ( fx+e \right ) \right ) ^{n}}{a+ia\tan \left ( fx+e \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left ({\left (A - i \, B\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + A + i \, B\right )} \left (\frac{2 \, c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}\right )^{n} e^{\left (-2 i \, f x - 2 i \, e\right )}}{2 \, a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \tan \left (f x + e\right ) + A\right )}{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{n}}{i \, a \tan \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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